Simplify and verify for $p=1$ and $q=1$$( iv)$. $\frac{-2}{3} pq^{2} \times( \frac{-3}{2}qp^{2})$

Given: $\frac{-2}{3} pq^{2} \times( \frac{-3}{2}qp^{2})$.

To do: To simplify and verify for $p=1$ and $q=1$.

Solution:  

$\frac{-2}{3} pq^{2} \times( \frac{-3}{2}qp^{2})$

$=\frac{-2}{3}\times\frac{-3}{2}\times pq^2\times qp^2$

$=p^3q^3$

$=(1)^3\times (1)^3$     [On substituting values $p=1$ and $q=1$. ]

$=1$

On substituting values $p=1$ and $q=1$ in $\frac{-2}{3} pq^{2} \times( \frac{-3}{2}qp^{2})$.

$\frac{-2}{3} pq^{2} \times( \frac{-3}{2}qp^{2})=\frac{-2}{3} \times 1\times( 1)^{2} \times( \frac{-3}{2}\times1\times( 1)^{2})=1$

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Updated on: 10-Oct-2022

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