- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of tire car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make (he shelter of height $2.5\ m$ with base dimensions $4\ m \times 3\ m$?
Given:
Ravish wanted to make a temporary shelter for his car by making a box-like structure with a tarpaulin that covers all four sides and the top of the tire car (with the front face as a flap which can be rolled up).
The shelter of height $2.5\ m$ with base dimensions $4\ m \times 3\ m$.
To do:
We have to find the area of the tarpaulin required.
Solution:
Length of the base $(l) = 4\ m$
Breadth of the base $(b) = 3\ m$
Height $(h) = 2.5\ m$
Therefore,
Area of tarpaulin used $=$ Area of the walls $+$ Area of the roof
$=2 h(l+b)+lb$
$=2 \times 2.5(4+3)+4 \times 3$
$=5 \times 7+12$
$=35+12$
$=47 \mathrm{~m}^{2}$
The area of the tarpaulin required is $47\ m^2$.
Advertisements
To Continue Learning Please Login
Login with Google