If $x = 1$ and $y = 6$ is a solution of the equation $8x - ay + a^2 = 0$, find the values of $a$.

Given:

$x = 1$ and $y = 6$ is a solution of the equation $8x - ay + a^2 = 0$.

To do:

We have to find the value of $a$.

Solution:

If $(x, y)$ is a solution of the equation $ax+by+c =0$, then it satisfies the given equation.

Therefore,

$8(1) -a(6)+a^2=0$

$a^2-6a+8=0$

$a^2-4a-2a+8=0$

$a(a-4)-2(a-4)=0$

$(a-4)(a-2)=0$

$a=4$ or $a=2$

The values of $a$ are $2$ and $4$. 

Tutorialspoint

Updated on: 10-Oct-2022

822 Views

Kickstart Your Career

Get certified by completing the course

Get Started