How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be $ 10 \mathrm{m} $ s $ ^{-2} $.

Given:

Mass of the dumbbell (m) = 10 kg

Distance covered by the dumbbell (s) = 80 cm = 0.8 m

Acceleration in the downward direction (a) = 10 m/s2

Initial velocity of the dumbbell (u) = 0

To find: Momentum

Solution:

According to the third equation of motion:

v2 = u2 + 2as

v2 = 0 + 2 x 10 x 0.8

v = 4 m/s

Hence, the momentum with which the dumbbell hits the floor is
⇒  p = mv

⇒ p = 10 × 4

⇒ p = 40 kg m/s

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Updated on: 10-Oct-2022

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