The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s. What is the gain in momentum per second?

 here given, mass of the body $m=10\ kg$

Initial velocity $u=4\ m/s$

Final velocity $v=8\ m/s$

Time $t=2\ s$

Here, initial momentum $P_1=mu=10\times4=40\ kg-m/s$

Final momentum $P_2=mv=10\times8=80\ kg-m/s$

Gain in momentum $\vartriangle P=P_2-P_1$

$=80-40=40\ kg.-m/s$

Therefore, gain in momentum per second $=\frac{\vartriangle P}{t}$

$=\frac{40\ kg-m/s}{2\ s}$

$=20\ kg.-m/s^2$

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Updated on: 10-Oct-2022

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