An object dropped from a cliff falls with a constant acceleration of $10\ m/s^2$. Find its velocity $5\ s$ after it was dropped.

Academic Physics NCERT Class 9

Here, Initial velocity $u=0$

Acceleration $a=10\ m/s^2$

Time $t=5\ s$

On using the first equation of the motion $v=u+at$

Or $v=0+10\times5$

Or $v=50\ m/s$

Therefore, velocity of the object after $5\ s$ is $50\ m/s$.

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Updated on: 10-Oct-2022

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