How long will it take a force of 10 N to stop a mass of 2.5 kg which is moving at 20 m/s?

Here given Force $F=10\ N$

Mass of the body $m=2.5\ kg$

Initial velocity $u=20\ m/s$

Final velocity $v=0$

Time $=?$

Using Newton's law of motion $F=ma$

Acceleration, $a=\frac{F}{m}$

$=\frac{10\ N}{2.5\ kg.}$

$=4\ m/s^2$

On using the first equation of motion, $v=u+at$

$0=20-4\times t$  [ take $a$ negative as it reduces the speed, so it is retardation]

Or $t=\frac{20}{4}$

Or $t=5\ s$

Therefore, it will take $5\ s$ for a force of $10\ N$ to stop a mass of $2.5\ kg$ which is moving at $20\ m/s$.

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Updated on: 10-Oct-2022

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