How many spherical lead shots of diameter $ 4 \mathrm{~cm} $ can be made out of a solid cube of lead whose edge measures $ 44 \mathrm{~cm} $.
Given:
Diameter of each spherical lead shot $=4\ cm$
Length of the edge of the solid cube of lead $=44\ cm$
To do:
We have to find the number of spherical lead shots that can be obtained.
Solution:
Radius of each spherical lead shot $=\frac{4}{2}\ cm$
$=2\ cm$
This implies,
Volume of each spherical lead shot $= \frac{4}{3} \pi r^3$
$=\frac{4}{3} \pi \times (2)^{3}$
$=\frac{4\pi}{3} \times 8$
$=\frac{32\pi}{3}$
Volume of the solid cube of lead $=s^3$
$=(44)^3$
Number of spherical lead shots that can be obtained $=\frac{\text { Volume of the solid cube of lead }}{\text { Volume of each spherical lead shot }}$
$=\frac{44\times44\times44}{\frac{32\pi}{3}}$
$=11\times21\times11$
$=121\times21$
$=2541$
The number of spherical lead shots that can be obtained is 2541.
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