A matchbox measures $ 4 \mathrm{~cm} \times 2.5 \mathrm{~cm} \times 1.5 \mathrm{~cm} $. What will be the volume of a packet containing 12 such boxes?
Given:
A matchbox measures \( 4 \mathrm{~cm} \times 2.5 \mathrm{~cm} \times 1.5 \mathrm{~cm} \).
To do:
We have to find the volume of a packet containing 12 such boxes.
Solution:
Length of the matchbox $l=4\ cm$
Breadth of the matchbox $b=2.5\ cm$
Height of the matchbox $h=1.5\ cm$
This implies,
The matchbox is in the shape of a cuboid.
Volume of the matchbox $= lbh$
$=4\times2.5\times1.5$
$=15\ cm^3$
Therefore,
Volume of 12 such matchboxes $= 12\times15$
$= 180\ cm^3$
Hence, the volume of 12 such boxes is $180\ cm^3$.
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