A matchbox measures $ 4 \mathrm{~cm} \times 2.5 \mathrm{~cm} \times 1.5 \mathrm{~cm} $. What will be the volume of a packet containing 12 such boxes?


Given:

A matchbox measures \( 4 \mathrm{~cm} \times 2.5 \mathrm{~cm} \times 1.5 \mathrm{~cm} \). 

To do:

We have to find the volume of a packet containing 12 such boxes.

Solution:

Length of the matchbox $l=4\ cm$

Breadth of the matchbox $b=2.5\ cm$

Height of the matchbox $h=1.5\ cm$

This implies,

The matchbox is in the shape of a cuboid.

Volume of the matchbox $= lbh$

$=4\times2.5\times1.5$

$=15\ cm^3$

Therefore,

Volume of 12 such matchboxes $= 12\times15$

$= 180\ cm^3$

Hence, the volume of 12 such boxes is $180\ cm^3$.

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Updated on: 10-Oct-2022

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