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How many litres of milk can a hemispherical bowl of diameter $ 10.5 \mathrm{~cm} $ hold?
Given:
The diameter of a hemispherical bowl is \( 10.5 \mathrm{~cm} \).
To do:
We have to find the volume of water it can hold.
Solution:
Diameter of the hemispherical bowl $= 10.5\ cm$
This implies,
Radius of the hemispherical bowl $r = \frac{10.5}{2}\ cm$
$= 5.25\ cm$
Therefore,
Volume of the hemispherical bowl $=\frac{2}{3} \pi r^{3}$
$=\frac{2}{3} \times \frac{22}{7} \times 5.25 \times 5.25 \times 5.25$
$=303.1875 \mathrm{~cm}^{3}$
We know that,
$1000 \mathrm{~cm}^{3}=1 \mathrm{~L}$
$1 \mathrm{~cm}^{3}=\frac{1}{1000} \mathrm{~L}$
This implies,
Volume $=303.1875 \mathrm{~cm}^{3}$
$=\frac{303.1875}{1000} \mathrm{~L}$
$=0.303 \mathrm{~L}$
The hemispherical bowl can hold $0.303\ L$ of milk.
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