How fast should a man of $50\ kg$ run so that his kinetic energy be $625\ J$?

Here given, mass fo the man $m=50\ kg$

Kinetic energy $K=625\ J$

Let $v$ be the speed of the man.

On using the equation of kinetic energy $K=\frac{1}{2}mv^2$

$625=\frac{1}{2}\times50\times v^2$

Or $1250=50v^2$

Or $v^2=\frac{1250}{50}$

Or $v^2=25$

Or $v=\sqrt{25}$

Or $v=5\ m/s$

Therefore, the man should run with the speed of $5\ m/s$ so that his kinetic energy becomes $625\ J$.

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Updated on: 10-Oct-2022

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