Hameed has built a cubical water tank with lid for his house, with each other edge $1.5\ m$ long. He gets the outer surface of the tank excluding the base, covered with square tiles of side $25\ cm$. Find how much he would spend for the tiles, if the cost of tiles is $Rs.\ 360$ per dozen.

Given:

Hameed has built a cubical water tank with lid for his house, with each other edge $1.5\ m$ long. He gets the outer surface of the tank excluding the base, covered with square tiles of side $25\ cm$. 

To do:

We have to find the amount he would spend for the tiles if the cost of tiles is $Rs.\ 360$ per dozen.

Solution:

Edge of the cubical tank $= 1.5\ m$

Area of the walls $= 4 (side)^2$

$= 4(1.5)^2$

$= 4 \times 2.25$

$= 9\ m^2$

Area of the floor $= (1.5)^2$

$= 2.25\ m^2$

Therefore,

Total surface area $= 9 + 2.25$

$= 11.25\ m^2$

Edge of a square tile $= 25\ cm$

$=0.25\ m$

This implies,

Area of a tile $= (0.25)^2$

$= 0.0625\ m^2$

Number of tiles required $=\frac{\text { Total area }}{\text { Area of } 1 \text { tile }}$

$=\frac{11.25}{0.0625}$

$=\frac{1125 \times 10000}{100 \times 625}$

$=180$

Cost of 12 tiles $=Rs.\ 360$

Cost of 180 tiles $=Rs.\ \frac{360 \times 180}{12}$

$= Rs.\ 5400$

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Updated on: 10-Oct-2022

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