Given that $1$ cubic cm of marble weighs $0.25\ kg$, the weight of marble block $28\ cm$ in width and $5\ cm$ thick is $112\ kg$. Find the length of the block.

Given:

$1$ cubic cm of marble weighs $0.25\ kg$, the weight of marble block $28\ cm$ in width and $5\ cm$ thick is $112\ kg$.

To do:

We have to find the length of the block.

Solution:

Weight of $1\ cm^3$ of marble $= 0.25\ kg$

Breadth of the block $(b) = 28\ cm$

Thickness of the block $(h) = 5\ cm$

Total weight of the block $= 112\ kg$

Therefore,

Volume $=\frac{112}{0.25}$

$=\frac{112 \times 100}{25}$

$=448 \mathrm{~cm}^{2}$

Length of the block $=\frac{\text { Volume }}{b \times h}$

$=\frac{448}{28 \times 5}$

$=\frac{16}{5}$

$=3.2 \mathrm{~cm}$

Hence, the length of the block is $3.2\ cm$.

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Updated on: 10-Oct-2022

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