A Metallic pipe is 0.7 cm thick. Inner radius of the pipe is 3.5 cm and length is 5 dm. Find the total surface area.


Given : 


Thickness of metallic pipe  =  0.7 cm

Inner Radius (r) = 3.5 cm

External Radius (R) = $3.5 + 0.7 = 4.2 $ cm

Length of pipe (h) = 5 d m  =  50 cm              (1 d m = 10 cm)

To do:


We have to find the total surface area.


Solution :


To find the total surface area of pipe, find all the surfaces on pipe and add.

 

Total surface area of pipe = Inner surface area $+$ External surface area $+$ Surface Areas of top and bottom

Inner Surface area : Curved surface area of inner pipe = 2πrh.

$2\ π\ r\ h\ =\ 2\ \times \ \frac{22}{7} \ \times \ 3.5\ \times \ 50\ $

                                                       

                 $=\ 2\ \times \ \frac{22}{2} \ \times \ 50$

               $=22\ \times \ 50\ \ =\ 1100$ cm           

       

Inner Surface area  = 1100 cm  

External Surface Area : Curved surface area of inner pipe = 2πRh

$2\ π\ R\ h\ =\ 2\ \times \ \frac{22}{7} \times \ 4.2\ \times \ 50$

$2πRh=2\times 22 \times 0.6 \times 50$

External Surface Area  =  1320 cm  

Areas of top and bottom :

Area of top surface = Area of Outer circle $-$ Area of inner Circle

Area of top surface = $π\ R^{2} \ -\ π\ r^{2}$

  

Take π as common, 

Area of top surface = $π\ \left( \ R^{2} \ -\ \ r^{2} \ \right)$

Area of top surface  = Area of bottom surface 

Surface areas of two circles =  Area of top surface $+$ Area of bottom surface 

Areas of top and bottom =$2\ π\ \left( \ R^{2} \ -\ \ r^{2} \ \right)$

                                                           

$$\displaystyle 2\ π\ \left( \ R^{2} \ -\ \ r^{2} \ \right) \ =\ 2\ π\ ( R\ +\ r) \ ( R\ -\ r) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left[ a^{2} \ -\ b^{2} \ =\ ( a+b)( a-b)\right]$$

$2\ π\ ( R\ +\ r) \ ( R\ -\ r) \ \ \ =\ 2\ \times \ \frac{22}{7}( 4.2\ +\ 3.5) \ ( 4.2\ -\ 3.5) \ $

$\ 2\ π\ ( R\ +\ r) \ ( R\ -\ r) \ \ \ =\ 2\ \times \ \frac{22}{7}( 7.7) \ ( 0.7) \ \ \ \ \ \ \ \ \ $

$2\ π\ ( R\ +\ r) \ ( R\ -\ r) \ \ \ =\ 33.88$ cm  

Areas of top and bottom = 33.88 cm   

Total Surface Area of Pipe  =  $1100\ +\ 1320\ +\ 33.88\ =\ 2453.88$ cm  

Total Surface Area of Pipe  =  2453.88 cm 2

Updated on: 10-Oct-2022

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