The perimeter of a rectangle is 91 cm. Its length is $(2x-1)$ cm and breadth is $(x+9)$ cm. Find its length and breadth.


Given:


Length of a rectangle$=(2x-1)$ cm.

Breadth of the rectangle$=(x+9)$ cm.

Perimeter of the rectangle$=91$ cm.

To do:


We have to find the length and breadth of the rectangle.

Solution:


We know that,

Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$.

Therefore,

$2(2x-1+x+9)=91$

$2(3x)+2(8)=91$

$6x=91-16$

$6x=75$

$x=\frac{75}{6}$

$x=\frac{25}{2}$


$2x-1=2(\frac{25}{2})-1=25-1=24$

$x+9=\frac{25}{2}+9=\frac{25+2(9)}{2}=\frac{43}{2}$

The length of the rectangle is $24$ cm and the breadth of the rectangle is $\frac{43}{2}$ cm.

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Updated on: 10-Oct-2022

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