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The perimeter of a rectangle is 91 cm. Its length is $(2x-1)$ cm and breadth is $(x+9)$ cm. Find its length and breadth.
Given:
Length of a rectangle$=(2x-1)$ cm.
Breadth of the rectangle$=(x+9)$ cm.
Perimeter of the rectangle$=91$ cm.
To do:
We have to find the length and breadth of the rectangle.
Solution:
We know that,
Perimeter of a rectangle of length $l$ and breadth $b$ is $2(l+b)$.
Therefore,
$2(2x-1+x+9)=91$
$2(3x)+2(8)=91$
$6x=91-16$
$6x=75$
$x=\frac{75}{6}$
$x=\frac{25}{2}$
$2x-1=2(\frac{25}{2})-1=25-1=24$
$x+9=\frac{25}{2}+9=\frac{25+2(9)}{2}=\frac{43}{2}$
The length of the rectangle is $24$ cm and the breadth of the rectangle is $\frac{43}{2}$ cm.
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