Find the value of $x$:
$ 9x+71=42 x+98 $

Given:

\( 9x+71=42 x+98 \)

To do:

We have to find the value of $x$.

Solution:

\( 9x+71=42 x+98 \)

$\Rightarrow 42x-9x=71-98$

$\Rightarrow 33x=-27$
$\Rightarrow x=\frac{-27}{33}$
$\Rightarrow x=\frac{-9}{11}$

The value of $x$ is $\frac{-9}{11}$.

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Updated on: 10-Oct-2022

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