Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Find the value of k, if $x + 1$ is a factor of $P(x) = kx^2 x + 2$.
Given :
$x + 1$ is a factor of $P(x) = kx^2 – x + 2$.
To do :
We have to find the value of k.
Solution :
Factor Theorem:
The factor theorem states that if p(x) is a polynomial of degree n > or equal to 1 and ‘a’ is any real number, then $x-a$ is a factor of p(x) if $p(a)=0$.
Therefore,
$x+1 = x-(-1)$ is a factor of $P(x) = kx^2 – x + 2$.
$P(-1) = k(-1)^2-(-1)+2 = 0$
$k(1)+1+2 = 0$
$k+3=0$
$k = -3$.
The value of k is $-3$.
Updated on: 10-Oct-2022
206 Views
Advertisements