Find all natural numbers that are 13 times greater than their last digit. Write the greatest and smallest one.
To do: Find all natural number that are 13times greater than their last digit
Solution:
For two digit number
Let ten's place digit be $x$, and unit's place digit be $y$
$10x+y = 13y$
$x=\frac{12y}{10}$
You can substitute $y = 5, x = 6$
So the number will be 65
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