Find all natural numbers that are 13 times greater than their last digit. Write the greatest and smallest one.


To do: Find all natural number that are 13times greater than their last digit


Solution:

For two digit number

Let ten's place digit be $x$, and unit's place digit be $y$

$10x+y = 13y$

$x=\frac{12y}{10}$

You can substitute $y = 5,  x = 6$

So the number will be 65


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Updated on: 10-Oct-2022

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