- Trending Categories
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Two natural numbers are such that they differ by 2, and their product is 48. Find the numbers.
Given :
Difference between two natural numbers is 2.
Product of the numbers is 48.
To find :
We have to find the numbers.
Solution :
Let the smaller number be 'x'.
Since the numbers differs by 2, let the greater number be $x+2$
Product of the numbers,
$x \times (x+2) = 48$
$x^2 + 2x = 48$
$x^2 + 2 x - 48 = 0$
Split the middle term into two terms, such that,
Their sum will be $2$, and their product will be $-48$.
$x^2 + 8x - 6x - 48 = 0$ $[8 - 6 = 2 ; 8 \times (-2) = -48]$
$x(x + 8) - 6 (x + 8) = 0$
$(x + 8) (x - 6) = 0$
$x = -8 , x = 6$
Natura number should be positive, so $x = 6$.
Greater number $= x + 2 = 6 + 2 = 8$.
Therefore, the natural numbers are 6 and 8.
Updated on: 10-Oct-2022
77 Views
Advertisements