# JavaScript - Find the smallest n digit number or greater

We are required to write a JavaScript function that takes in a number as the first argument, say n, and an array of numbers as the second argument. The function should return the smallest n digit number which is a multiple of all the elements specified in the array. If there exist no such n digit element then we should return the smallest such element.

For example: If the array is −

const arr = [12, 4, 5, 10, 9]

For both n = 2 and n = 3, the output should be 180

## Example

Following is the code −

const arr = [12, 4, 5, 10, 9]
const num1 = 2;
const num2 = 3;
const allDivides = (arr, num) => arr.every(el => num % el === 0);
const smallestMultiple = (arr, num) => {
let smallestN = Math.pow(10, (num - 1));
while(!allDivides(arr, smallestN)){
smallestN++;
};
return smallestN;
};
console.log(smallestMultiple(arr, num1));
console.log(smallestMultiple(arr, num2));

## Output

Following is the output in the console −

180
180

Updated on: 16-Sep-2020

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