Eleven bags of wheat flour, each marked $ 5 \mathrm{~kg} $, actually contained the following weights of flour (in $ \mathrm{kg} $ ):
$ \begin{array}{lllllllllll}4.97 & 5.05 & 5.08 & 5.03 & 5.00 & 5.06 & 5.08 & 4.98 & 5.04 & 5.07 & 5.00\end{array} $
Find the probability that any of these bags chosen at random contains more than $ 5 \mathrm{~kg} $ of flour.

Given:

Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour

(in kg):

4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98, 5.04, 5.07, 5.00

To do:

We have to find the probability that any of the bags chosen at random contains more than 5 kg of flour.

Solution:

Total number of wheat flour bags $=11$

Number of bags that contain more than 5 kg of flour $=7$

We know that,

Probability of an event=$ \frac{Number \ of \ favourable \ outcomes}{Total \ number \ of \ outcomes}$

Therefore,

Probability that the bag chosen contains more than 5 kg of flour $=\frac{7}{11}$

$=0.6363$

This implies,

The probability that the bag chosen contains more than 5 kg of flour is $0.6363$.  

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Updated on: 10-Oct-2022

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