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An angle is $ 10^{\circ} $ more than its complement, find the angle.
Given:
An angle is \( 10^{\circ} \) more than its complement.
To do:
We have to find the measure of the angle.
Solution:
An angle is said to be the complement of another angle if the sum of both the angles is $90^o$.
If $x$ is an angle, then its complement is $90^o - x$.
Let the required angle be $x$.
This implies,
Complement of angle $x=90^o-x$
According to the question,
$x=(90^o-x)+10^o$
$x=90^o-x+10^o$
$x+x=100^o$
$x=\frac{100^o}{2}$
$x=50^o$
Hence, the required angle is $50^o$.
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