An angle is $14^o$ more than its complementary angle. What is its measure?

Given:

An angle is $14^o$ more than its complementary angle.

To do:

We have to find its measure.

Solution:

Two angles are said to be complementary if the sum of their measures is $90^o$.

Let the required angle be $x$.

This implies,

The measure of the complementary angle $=x-14^o$

Therefore,

$x+x-14^o=90^o$

$2x=90^o+14^o$

$x=\frac{104^o}{2}$

$x=52^o$

The measure of the required angle is $52^o$.