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An angle is $14^o$ more than its complementary angle. What is its measure?
Given:
An angle is $14^o$ more than its complementary angle.
To do:
We have to find its measure.
Solution:
Two angles are said to be complementary if the sum of their measures is $90^o$.
Let the required angle be $x$.
This implies,
The measure of the complementary angle $=x-14^o$
Therefore,
$x+x-14^o=90^o$
$2x=90^o+14^o$
$x=\frac{104^o}{2}$
$x=52^o$
The measure of the required angle is $52^o$.
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