A perging lens has a focal length of 3 cm. Calculate the power.

Given: 

Focal length, $f$ = $-$3 cm = $-$0.03 m  $(\because lens\ is\ diverging\ in\ nature,\ focal\ length\ will\ be\ negative)$

To find: ​​Power of a lens, $P$.

Solution:

We know that power of the lens is given by-

$Power\ (P)=\frac {1}{f}$

Substituting the given value we get-

 $P=\frac {1}{-0.03}$

 $P=-\frac {100}{3}$

 $P=-33.33D$

Hence, the power of the lens is 33.33 D.

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Updated on: 10-Oct-2022

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