A perging lens has a focal length of 0.10 m. The power of this lens will be :(a) +10.0D (b) +1.0D (c) −1.0D (d) −10.0D

(d) -10.0D

Explanation

Given:

Focal length of the lens, $f$ = $-$0.10 m $(\because lens\ is\ diverging\ in\ nature,\ focal\ length\ will\ be\ negative)$

To find: Power of the lens, $P$.

Solution:

Power of a lens is given by-

$P=\frac {1}{f}$

Substituting the given values we get-

$P=\frac {1}{-0.10}$

$P=-\frac {100}{10}$

$P=-10D$

Thus, the power of the lens, $P$ is 10 D or 10.0 D. 

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

36 Views

Kickstart Your Career

Get certified by completing the course

Get Started