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A convergent lens of focal length 8cm combined with a diverging lens of power -10D. Calculate the focal length of the combination.
Given, focal length of the convergent lens (convex lens) = f = 8cm = 0.08m.
Therefore, its power is:
$P=\frac{1}{f(meters)}$
$P=\frac{1}{0.08}$
$P=\frac{100}{8}$
$P=12.5D$
As the power of the diverging lens (concave lens) is -10D, therefore, the power of the combination is $=12.5D+(-10D)=12.5D-10D=2.5D$
The focal length of the system of lens
$f=\frac{1}{P}$
$f=\frac{1}{2.5}$
$f=\frac{10}{25}$
$f=+0.4m$
$f=40cm$
Hence, the focal length of the combination will be $40cm$.
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