A man weighing 500 N carried a load of 100 N up a flight of stairs 4 m high in 5 seconds. What is the power?


Given, weight of the man $W_1=500\ N$

Weight carried by man $W_2=100\ N$

So, total weight $mg=W_1+W_2=500\ N+100\ N=600\ N$

Height $h=4\ m$

Time $=5\ s$

Therefore, work done to carry the weight $=mgh$

$=600\ N\times4\ m$

$=2400\ Joule$

Therefore, power $=\frac{work\ done}{time}$

$=\frac{2400\ J}{5\ s}$

$=480\ W$

Therefore, power is $480\ W$.

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Updated on: 10-Oct-2022

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