- Trending Categories
Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
A car of weight 20000 N climbs up a hill at a steady speed of 8 m/s, gaining a height of 120 m in 100 s. Calculate:
(a) work done by the car.
(b) power of engine of car.
Here given, weight of the car $mg=20000\ N$
Height gained by the car $h=120\ m$
Time $t=100\ s$
Speed of the car $v=8\ m/s$
(a). Work done by the car to climb $=mgh$
$=20000\ N\times120\ m$
$=2400000\ Joule$
$=2400\ kJ$ [Because $1kJ=1000\ J$]
Therefore, work done by the car is $2400\ kJ$.
(b). Power of the engine $=\frac{work\ done}{time}$
$=\frac{2400000\ J}{100\ s}$
$=24000\ W$
$=24\ kW$ [Because $1\ kW=1000\ Watt$]
Advertisements