A man goes 10 m due south and then 24 m due west. How far is he from the starting point?


Given: A man goes 10 m due south and then 24 m due west.

To find: Here we have to find the distance of the man from starting point.

Solution:

Assume the path traveled by the man as a triangle.





As the man travels in a straight path and turns at the angle of 90°, by Pythagoras theorem,


AC2 = AB2 + BC2  

AC2 = 242 + 102 m 

AC2 = 576 + 100 m 

AC2 = 676 m

AC = $\sqrt{676}$ m

AC = 26 m


So, the man is 26 m from the starting point.

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Updated on: 10-Oct-2022

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