A ship sails due east 30 kilometre and then due south for 16 kilometre. How far in a direct line is it from the starting point?

Given: 

A ship sails due east 30 kilometre and then due south for 16 kilometre.

To do: 

Here we have to find the distance of the ship from the starting point.

Solution:

The path of the ship can be depicted as below:

As the ship travels in a straight path and turns at the angle of 90°, by Pythagoras theorem,

$AB^2+BC^2=AC^2$

$(30)^2+(16)^2=AC^2$

$900+256=AC^2$

$AC^2=1156$

$AC=\sqrt{1156}$

$AC=34\ km$

Therefore, the ship is 34 km from the starting point.

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Updated on: 10-Oct-2022

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