A helicopter flies at a speed of $923 \times 10^{4} $m/hour. How long will it take to cover a distance of 320 km?

Given :

Speed of the helicopter $923 \times 10^{4} $m/hour.

To do :

We have to find the time taken to cover a distance of 320 km.

Solution :

$923 \times 10^{4} m/hour = 92300 m/hr$.

We know that,

$1 km = 1000 m$

$1 m = \frac{1}{1000} km$

Therefore,

Speed of the helicopter $= \frac{92300}{1000} km/hr = 92.3 km/hr$

This implies,

Time taken to cover a distance of 92.3 km $= 1 hour = 60 min$.

Time taken to cover a distance of 320 km $= \frac{(320\times 60)}{92.3} min$

$= \frac{19200}{92.3} min $

$= \frac{192000}{923} min $

$= 208 min$

$= 3 hours 28 minutes$.

Therefore, the time taken to cover 320 km is 3 hrs 28 minutes.

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Updated on: 10-Oct-2022

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