A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be $55$ minus the number of articles produced in a day. On a particular day, the total cost of production was Rs. $750$. If x denotes the number of toys produced that day, form the quadratic equation to find $x$.

Given:

A cottage industry produces a certain number of toys in a day.

The cost of production of each toy (in rupees) was found to be $55$ minus the number of articles produced in a day.

On a particular day, the total cost of production was Rs. $750$. $x$ denotes the number of toys produced that day.

To do:

Here, we have to form the quadratic equation to find $x$.
 

Solution:

The cost of production of each toy $= 55 - x$

The total cost of production is the product of the number of toys produced in a day and the cost of production of each toy $ =x (55 - x)$

Therefore,

$x(55-x) = 750$

$55x-x^2 = 750$

$x^2-55x+750 = 0$

The required quadratic equation is $x^2 – 55x + 750 = 0$.

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Updated on: 10-Oct-2022

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