# Find number of times every day occurs in a Year in Python

When it is required to find the number of times every day of the week occurs in a year, a list is defined, and it is iterated over, and is count is incremented respectively.

Below is a demonstration of the same −

## Example

Live Demo

import math
def num_of_occurrence( n, firstday):

my_days = [ "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday","Sunday" ]

my_count= [4 for i in range(0,7)]

my_position = -1
for i in range(0,7):
if (first_day == my_days[i]):
my_position = i
break

inc = n - 28

for i in range( my_position, my_position + inc):
if (i > 6):
my_count[i % 7] = 5
else:
my_count[i] = 5

for i in range(0,7):
print (my_days[i] , " " , my_count[i])

num = 31
first_day = "Thursday"
num_of_occurrence(num, first_day)

## Output

Monday 4
Tuesday 4
Wednesday 4
Thursday 5
Friday 5
Saturday 5
Sunday 4

## Explanation

• The required packages are imported.

• A method named ‘num_of_occurence’ is defined that takes a number and a day of week as parameter.

• A list with number of days of week is defined.

• Another list with numbers in the range of 0 and 7 is defined.

• The range is iterated over, and if the day passed as parameter matches a day from the list, its position is set.

• Another iteration is used and the count of every day of the week is incremented depending on the day passed as first day to the method.

• The method is called by passing the respective parameters.

• The output is displayed on the console.