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A body is moving uniformly in a straight line with a velocity of $5\ m/s$. Find graphically the distance covered by it in $5\ seconds$.
The motion of the boy is shown as below :
The distance covered in $5\ s$ will be equal to the area under AB in the graph.
So, the distance covered $=$ area of rectangle OABC
$=5\ m/s\times5\ s$
$=25\ m$
Therefore, the distance covered is $25\ m$.
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