A balloon is connected to a meteorological ground station by a cable of length $ 215 \mathrm{~m} $ inclined at $ 60^{\circ} $ to the horizontal. Determine the height of the balloon from the ground. Assume that there is no slack in the cable.
Given:
A balloon is connected to a meteorological ground station by a cable of length \( 215 \mathrm{~m} \) inclined at \( 60^{\circ} \) to the horizontal.
To do:
We have to determine the height of the balloon from the ground.
Solution:
Let $C$ be the meteorological ground station and $AB$ be the height of the balloon from the ground.
From the figure,
$\mathrm{BC}=215 \mathrm{~m}, \angle \mathrm{BCA}=60^{\circ}$
Let the height of the balloon from the ground be $\mathrm{AB}=h \mathrm{~m}$.
We know that,
$\sin \theta=\frac{\text { Opposite }}{\text { Hypotenuse }}$
$=\frac{\text { AB }}{BC}$
$\Rightarrow \sin 60^{\circ}=\frac{h}{215}$
$\Rightarrow \frac{\sqrt3}{2}=\frac{h}{215}$
$\Rightarrow (215)\frac{\sqrt3}{2}=h \mathrm{~m}$
$\Rightarrow h=\frac{215(1.732)}{2} \mathrm{~m}$
$\Rightarrow h=185.975 \mathrm{~m}$
$\Rightarrow h=186 \mathrm{~m}$
Therefore, the height of the balloon from the ground is $186 \mathrm{~m}$.
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