(a) \( \frac{1}{6} \square \frac{1}{3} \)
(b) \( \frac{3}{4} \square \frac{2}{6} \)
(c) \( \frac{2}{3} \square \frac{2}{4} \)
(d) \( \frac{6}{6} \square \frac{3}{3} \)
(e) \( \frac{5}{6} \square \frac{5}{5} \)

" ">

Look at the figures and write 's' or ' \( > \) ', '- ' between the given pairs of fractions.

(a) \( \frac{1}{6} \square \frac{1}{3} \)
(b) \( \frac{3}{4} \square \frac{2}{6} \)
(c) \( \frac{2}{3} \square \frac{2}{4} \)
(d) \( \frac{6}{6} \square \frac{3}{3} \)
(e) \( \frac{5}{6} \square \frac{5}{5} \)

"


To do:

We have to write '$<$' or ' \( > \) ', '$=$' between the given pairs of fractions.

Solution:

(a) From the figure,

The area occupied by $\frac{1}{3}$ is greater than the area occupied by $\frac{1}{6}$

This implies,

$\frac{1}{3}>\frac{1}{6}$

Therefore,

$\frac{1}{6} < \frac{1}{3}$

(b) From the figure,

The area occupied by $\frac{3}{4}$ is greater than the area occupied by $\frac{2}{6}$

This implies,

$\frac{3}{4}>\frac{2}{6}$

(c) From the figure,

The area occupied by $\frac{2}{3}$ is greater than the area occupied by $\frac{2}{4}$

This implies,

$\frac{2}{3}>\frac{2}{4}$

(d) From the figure,

The area occupied by $\frac{6}{6}$ is equal to the area occupied by $\frac{3}{3}$

This implies,

$\frac{6}{6} =\frac{3}{3}$

(e) From the figure,

The area occupied by $\frac{5}{5}$ is greater than the area occupied by $\frac{5}{5}$

This implies,

$\frac{5}{5}>\frac{5}{6}$

Therefore,

$\frac{5}{6} < \frac{5}{5}$

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