Fill in the missing fractions.
(a) $ \frac{7}{10}-\square=\frac{3}{10} $
(b) $ \square-\frac{3}{21}=\frac{5}{21} $
(c) $ \square-\frac{3}{6}=\frac{3}{6} $
(d) $ \square+\frac{5}{27}=\frac{12}{27} $

AcademicMathematicsNCERTClass 6

To do :

We have to find the missing fractions. 

Solution :

(a) Let the missing fraction be $x$

This implies, 

$\frac{7}{10}-x=\frac{3}{10}$

$x=\frac{7}{10}-\frac{3}{10}$

$x=\frac{7-3}{10}$

$x=\frac{4}{10}$

$x=\frac{2}{5}$

Therefore, the missing fraction is $\frac{2}{5}$.

(b) Let the missing fraction be $x$

This implies, 

$x-\frac{3}{21}=\frac{5}{21}$

$x=\frac{5}{21}+\frac{3}{21}$

$x=\frac{5+3}{21}$

$x=\frac{8}{21}$

Therefore, the missing fraction is $\frac{8}{21}$.

(c) Let the missing fraction be $x$

This implies, 

$x-\frac{3}{6}=\frac{3}{6}$

$x=\frac{3}{6}+\frac{3}{6}$

$x=\frac{3+3}{6}$

$x=\frac{6}{6}$

$=1$

Therefore, the missing fraction is $1$.

(d) Let the missing fraction be $x$

This implies, 

$x+\frac{5}{27}=\frac{12}{27}$

$x=\frac{12}{27}-\frac{5}{27}$

$x=\frac{12-5}{27}$

$x=\frac{7}{27}$

Therefore, the missing fraction is $\frac{7}{27}$.

raja
Updated on 10-Oct-2022 13:33:02

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