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is_link() function in PHP
The is_link() function checks whether a file is a symbolic link or not. It returns TRUE, if the file exists and is a symbolic link. On failure, it returns FALSE.
Syntax
is_link(file_path)
Parameters
file_path − The file to check
Return
The is_link() function returns TRUE, if the file exists and is a symbolic link. On failure, it returns FALSE.
Example
<?php
$mylink = "new";
if(is_link($mylink)) {
echo ("link");
} else {
echo ("not a link");
}
?>Output
not a link
Let us see another example.
Example
<?php
$mylink = "documents";
if(is_link($mylink)) {
echo ("link");
} else {
echo ("not a link");
}
?>Output
not a link
Updated on: 24-Jun-2020
83 Views
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