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If $ \mathrm{A}, \mathrm{B}, \mathrm{C} $ are three points on a line such that $ \mathrm{AB}=5 \mathrm{~cm}, \mathrm{BC}=3 \mathrm{~cm} $ and $ \mathrm{AC}=8 \mathrm{~cm} $, which one of them lies between the other two?
Given:
\( \mathrm{A}, \mathrm{B}, \mathrm{C} \) are three points on a line such that \( \mathrm{AB}=5 \mathrm{~cm}, \mathrm{BC}=3 \mathrm{~cm} \) and \( \mathrm{AC}=8 \mathrm{~cm} \)
To do:
We have to find which one of them lies between the other two.
Solution:
Here,
$AB + BC=5+3$
$=8\ cm$
$AC=8\ cm$
Therefore, point B lies between points A and C.
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