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How to place X-axis grid over a spectrogram in Python Matplotlib?
To place X-axis grid over a spectrogram in Python, we can use grid() method and take the following steps −
- Set the figure size and adjust the padding between and around the subplots.
- Create t, s1, s2, nse, x, NEFT and Fs data points using numpy.
- Create a new figure or activate an existing figure using subplots() method with nrows=2.
- Plot t and x data points using plot() method.
- Lay out a grid in current line style.
- Set X-axis margins.
- Plot a spectrogram using specgram() method.
- Lay out a grid in current line style with dotted linestyle and some other properties.
- To display the figure, use show() method.
Example
import matplotlib.pyplot as plt import numpy as np plt.rcParams["figure.figsize"] = [7.50, 3.50] plt.rcParams["figure.autolayout"] = True dt = 0.0005 t = np.arange(0.0, 20.0, dt) s1 = np.sin(2 * np.pi * 100 * t) s2 = 2 * np.sin(2 * np.pi * 400 * t) s2[t <= 10] = s2[12 <= t] = 0 nse = 0.01 * np.random.random(size=len(t)) x = s1 + s2 + nse NFFT = 1024 Fs = int(1.0 / dt) fig, (ax1, ax2) = plt.subplots(nrows=2) ax1.plot(t, x) ax1.grid(axis="x", ls="dotted", lw=2, color="red") ax1.margins(x=0) Pxx, freqs, bins, im = ax2.specgram(x, NFFT=NFFT, Fs=Fs, noverlap=900) ax2.grid(axis="x", ls="dotted", lw=2, color="red") plt.show()
Output
Updated on: 03-Jun-2021
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