Find the sum of the following APs:
$-37, -33, -29$ …… to $12$ terms.
 Given:
Given AP is $-37, -33, -29$ ……
To do:
We have to find the sum of the given A.P. to 12 terms.
Solution:
$a=-37, d=-33-(37)=-33+37=4, n=12$
We know that,
$S_{n}=\frac{n}{2}[2 a+(n-1) d]$
$S_{12}=\frac{12}{2}[2 \times(-37)+(12-1) 4]$
$=6(-74+44)$
$=6 \times(-30)$
$=-180$
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