Which of the following are APs? If they form an AP, find the common difference $d$ and write three more terms.
$0, -4, -8, -12, …..$
Given:
Given sequence is $0, -4, -8, -12, …..$
To do:
We have to check whether the given sequence is an AP. If it is an AP we have to find the common difference $d$ and write three more terms.
Solution:
In the given sequence,
$a_1=0, a_2=-4, a_3=-8$
$a_2-a_1=-4-(0)=-4$
$a_3-a_2=-8-(-4)=-8+4=-4$
$a_2 - a_1 = a_3 - a_2$
$d=a_2 - a_1=-4$
$a_5=a_4+d=-12+(-4)=-16$
$a_6=a_5+d=-16+(-4)=-20$
$a_7=a_6+d=-20+(-4)=-24$
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