Find the sum of the following arithmetic progressions: $ 1,3,5,7, \ldots $ to 12 terms

Given:

Given A.P. is \( 1,3,5,7, \ldots \)

To do:

We have to find the sum of the given A.P. to 12 terms.

Solution:

Here, \( a=1, d=3-1=2 \) and \( n=12 \)

We know that

$S_{n}=\frac{n}{2}[2 a+(n-1) d]$ 

$\therefore S_{12}=\frac{12}{2}[2 \times 1+(12-1) \times 2]$

$=6[2+11 \times 2]$ 

$=6[2+22]$

$=6 \times 24$

$=144$

The sum of the given A.P. to 12 terms is 144.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

64 Views

Kickstart Your Career

Get certified by completing the course

Get Started