Find the sum of the following APs:
$0.6, 1.7, 2.8, ……$ to $100$ terms.

 Given:

Given AP is $0.6, 1.7, 2.8, ……$ 

To do:

We have to find the sum of the given A.P. to 100 terms.

Solution:

$a=0.6, d=1.7-0.6=1.1, n=100$

We know that,

$S_{n}=\frac{n}{2}[2 a+(n-1) d]$

$S_{100}=\frac{100}{2}[2 \times 0.6+(100-1) 1.1]$

$=50(1.2+108.9)$

$=50 \times 110.1$

$=5505$

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Updated on: 10-Oct-2022

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