Find the number of consecutive zero at the end after multiplying n numbers in Python

Python Server Side Programming Programming

Suppose we have an array with n numbers, we have to return the number of consecutive zero’s at the end after multiplying all the n numbers.

So, if the input is like [200, 20, 5, 30, 40, 14], then the output will be 6 as 200 * 20 * 5 * 30 * 40 * 14 = 336000000, there are six 0s at the end.

To solve this, we will follow these steps −

Define a function count_fact_two() . This will take n
count := 0
while n mod 2 is 0, do
- count := count + 1
- n := n / 2 (only the quotient as integer)
return count
Define a function count_fact_five() . This will take n
count := 0
while n mod 5 is 0, do
- count := count + 1
- n := n / 5 (only the quotient as integer)
return count
From the main method, do the following −
n := size of A
twos := 0, fives := 0
for i in range 0 to n, do
- twos := twos + count_fact_two(A[i])
- fives := fives + count_fact_five(A[i])
if twos − fives, then
- return twos
otherwise,
- return fives

Example

Let us see the following implementation to get better understanding −

Live Demo

def count_fact_two( n ):
   count = 0
   while n % 2 == 0:
      count+=1
      n = n // 2
   return count
def count_fact_five( n ):
   count = 0
   while n % 5 == 0:
      count += 1
      n = n // 5
   return count
def get_consecutive_zeros(A):
   n = len(A)
   twos = 0
   fives = 0
   for i in range(n):
      twos += count_fact_two(A[i])
      fives += count_fact_five(A[i])
   if twos < fives:
      return twos
   else:
      return fives
A = [200, 20, 5, 30, 40, 14]
print(get_consecutive_zeros(A))

Input

[200, 20, 5, 30, 40, 14]

Output

Arnab Chakraborty

Updated on 27-Aug-2020 06:10:40

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