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The sum of the three consecutive even number is 96. Find the numbers.
Given: Sum of the three consecutive even number is 96.
To find: Here we have to find three consecutive even numbers whose sum is 96.
Solution:
Let the first number be = $x$
Then,
The next consecutive even number would be = $x\ +\ 2$
And,
The following consecutive even number would be = $x\ +\ 4$
Then put those 3 expressions together to make:
$x\ +\ (x\ +\ 2)\ +\ (x\ +\ 4)\ =\ 96$
Combine like terms to:
$3x\ +\ 6\ =\ 96$
Subtract 6 from each side:
$3x\ =\ 90$
Divide both sides by 3:
$x\ =\ 30$
Therefore,
The first number be = $x$ = 30
The next consecutive even number would be = $x\ +\ 2$ = $30\ +\ 2$ = 32
The following consecutive even number would be = $x\ +\ 4$ = $30\ +\ 4$ = 34
So, required three consecutive even numbers are 30, 32 and 34.
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