# Find:(a) $\frac{1}{2}$ of (i) $24$ and (ii) $46$(b) $\frac{2}{3}$ of (i) $18$ and (ii) $27$(c) $\frac{3}{4}$ of (i) $16$ and (ii) $36$ (d) $\frac{4}{5}$ of (i) $20$ and (ii) $35$

To do:

We have to find:

(a) $\frac{1}{2}$ of (i) $24$ and (ii) $46$

(b) $\frac{2}{3}$ of (i) $18$ and (ii) $27$

(c) $\frac{3}{4}$ of (i) $16$ and (ii) $36$

(d) $\frac{4}{5}$ of (i) $20$ and (ii) $35$

Solution:

(a)

(i) $\frac{1}{2}$ of $24=\frac{1}{2}\times24$

$=12$

(ii) $\frac{1}{2}$ of $46=\frac{1}{2}\times46$

$=23$

(b)

(i) $\frac{2}{3}$ of $18=\frac{2}{3}\times18$

$=\frac{(2\times18)}{3}$

$=\frac{36}{3}$

$=12$

(ii) $\frac{2}{3}$ of $27=\frac{2}{3}\times27$

$=2\times9$

$=18$

(c)

(i) $\frac{3}{4}$ of $16=\frac{3}{4}\times16$

$=3\times4$

$=12$

(ii) $\frac{3}{4}$ of $36=\frac{3}{4}\times36$

$=3\times9$

$=27$

(d)

(i) $\frac{4}{5}$ of $20=\frac{4}{5}\times20$

$=4\times4$

$=16$

(ii) $\frac{4}{5}$ of $35=\frac{4}{5}\times35$

$=4\times7$

$=28$

Updated on: 10-Oct-2022

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