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Find the reciprocal of :
i) $\frac{2}{-5} \times \frac{3}{-7}$
ii) $\frac{-4}{3} \times \frac{-5}{-8}$
Given :
The given terms are,
i) $\frac{2}{-5} \times \frac{3}{-7}$
ii) $\frac{-4}{3} \times \frac{-5}{-8}$
To find :
We have to find the reciprocal of the given terms.
Solution :
Reciprocal of i) $\frac{2}{-5} \times \frac{3}{-7}$
$\frac{2}{-5} \times \frac{3}{-7} = \frac{6}{35}$ $[- \times - = +]$
Reciprocal of $\frac{6}{35}$ is $\frac{35}{6}$.
Therefore, the reciprocal of $\frac{2}{-5} \times \frac{3}{-7}$ is $\frac{35}{6}$.
Reciprocal of ii) $\frac{-4}{3} \times \frac{-5}{-8}$
$\frac{-4}{3} \times \frac{-5}{-8} = \frac{20}{-24}$ $[- \times + = -]$
Reciprocal of $\frac{20}{-24}$ is $\frac{-24}{20}$
Therefore, the reciprocal of $\frac{-4}{3} \times \frac{-5}{-8}$ is $\frac{-24}{20}$.
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