Find the reciprocal of :
i) $\frac{2}{-5} \times \frac{3}{-7}$
ii) $\frac{-4}{3} \times \frac{-5}{-8}$

Given : 

The given terms are,

i) $\frac{2}{-5} \times \frac{3}{-7}$

ii) $\frac{-4}{3} \times \frac{-5}{-8}$

 

To find :

We have to find the reciprocal of the given terms.

Solution :

Reciprocal of  i) $\frac{2}{-5} \times \frac{3}{-7}$

$\frac{2}{-5} \times \frac{3}{-7} = \frac{6}{35}$                      $[- \times - = +]$

Reciprocal of $\frac{6}{35}$ is $\frac{35}{6}$.

Therefore, the reciprocal of  $\frac{2}{-5} \times \frac{3}{-7}$ is  $\frac{35}{6}$.

Reciprocal of ii) $\frac{-4}{3} \times \frac{-5}{-8}$

 $\frac{-4}{3} \times \frac{-5}{-8} = \frac{20}{-24}$               $[- \times + = -]$

Reciprocal of $\frac{20}{-24}$ is $\frac{-24}{20}$

Therefore, the reciprocal of $\frac{-4}{3} \times \frac{-5}{-8}$ is $\frac{-24}{20}$.