Evalute:
(i) $(5)^{-2}$
(ii) $(-3)^{-2}$
(iii) $(\frac{1}{3})^{-4}$
(iv) $(\frac{-1}{2})^{-1}$
To do:
We have to evaluate the given rational numbers.
Solution:
We know that,
$a^{-m}=\frac{1}{a^m}$
Therefore,
(i) $5^{-2}=\frac{1}{5^2}$
$=\frac{1}{25}$
(ii) $(-3)^{-2}=\frac{1}{(-3)^{2}}$
$=\frac{1}{(-3) \times(-3)}$
$=\frac{1}{9}$
(iii) $(\frac{1}{3})^{-4}=(\frac{3}{1})^{4}$
$=3 \times 3 \times 3 \times 3$
$=81$
(iv) $(\frac{-1}{2})^{-1}=(-2)^{1}$
$=-2$
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