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Find:
(i) $ 64^{\frac{1}{2}} $
(ii) $ 32^{\frac{1}{5}} $
(iii) $ 125^{\frac{1}{3}} $
To do:
We have to find the values of
(i) \( 64^{\frac{1}{2}} \)
(ii) \( 32^{\frac{1}{5}} \)
(iii) \( 125^{\frac{1}{3}} \)
Solution:
We know that,
$(a^m)^n=(a)^{mn}$
Therefore,
(i) $64^{\frac{1}{2}}=(8\times8)^{\frac{1}{2}}$
$=(8^2)^{\frac{1}{2}}$
$=(8)^{2\times\frac{1}{2}}$
$=8^1$
$=8$
Hence $64^{\frac{1}{2}}=8$
(ii) $32^{\frac{1}{5}}=(2\times2\times2\times2\times2)^{\frac{1}{5}}$
$=(2^5)^{\frac{1}{5}}$
$=(2)^{5\times\frac{1}{5}}$
$=2^1$
$=2$
Hence $32^{\frac{1}{5}}=2$
(iii) $125^{\frac{1}{3}}=(5\times5\times5)^{\frac{1}{3}}$
$=(5^3)^{\frac{1}{3}}$
$=(5)^{3\times\frac{1}{3}}$
$=5^1$
$=5$
Hence $125^{\frac{1}{3}}=5$
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